Algebra 2 (HS pathway)

Polynomial Functions: Operations, Factoring, and Complex Numbers

Algebra 2

  • ✓By the end of this lesson students will be able to perform addition, subtraction, multiplication, and division of polynomial functions.
  • ✓By the end of this lesson students will be able to factor polynomial functions completely over the complex numbers using various techniques, including the Rational Root Theorem and synthetic division.
  • ✓By the end of this lesson students will be able to understand and apply the Fundamental Theorem of Algebra to determine the number of roots of a polynomial function.
  • ✓By the end of this lesson students will be able to perform operations with complex numbers and use the Conjugate Root Theorem to find all roots of polynomial equations with real coefficients.
  • ✓By the end of this lesson students will be able to construct polynomial functions given their roots, including complex conjugate pairs.

Key concepts

Polynomial Functions

A polynomial function is a function of the form P(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0, where n is a non-negative integer (the degree), and a_n, a_{n-1}, ..., a_0 are real coefficients with a_n ≠ 0. a_n is the leading coefficient, and a_0 is the constant term. Polynomials are typically written in standard form, with terms ordered from highest to lowest degree.

P(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0
Operations on Polynomials

Operations on polynomials include addition, subtraction, multiplication, and division.\n* Addition/Subtraction: Combine like terms (terms with the same variable and exponent).\n* Multiplication: Use the distributive property (e.g., FOIL for binomials, or distribute each term of one polynomial to every term of the other).\n* Division:\n * Long Division: A method similar to numerical long division.\n * Synthetic Division: A shortcut for dividing a polynomial by a linear factor of the form (x - k). It is generally faster and less prone to arithmetic errors than long division for these specific cases.

Factoring Polynomials

Factoring is the process of breaking down a polynomial into a product of simpler polynomials (factors).\n* Greatest Common Factor (GCF): Always look for this first.\n* Special Forms: Difference of Squares (a^2 - b^2 = (a-b)(a+b)), Sum/Difference of Cubes (a^3 + b^3 = (a+b)(a^2-ab+b^2), a^3 - b^3 = (a-b)(a^2+ab+b^2)).\n* Grouping: Useful for polynomials with four terms.\n* Rational Root Theorem: If a polynomial P(x) has integer coefficients, then every rational root of P(x) = 0 has the form p/q, where p is a factor of the constant term a_0 and q is a factor of the leading coefficient a_n.\n* Factor Theorem: A polynomial P(x) has a factor (x - k) if and only if P(k) = 0.\n* Remainder Theorem: If a polynomial P(x) is divided by (x - k), the remainder is P(k).

Complex Numbers

A complex number is a number of the form a + bi, where a and b are real numbers, and i is the imaginary unit, defined as i = sqrt(-1). Therefore, i^2 = -1. 'a' is the real part and 'b' is the imaginary part.\n* Operations:\n * Addition/Subtraction: Combine real parts and imaginary parts separately: (a + bi) ± (c + di) = (a ± c) + (b ± d)i.\n * Multiplication: Use the distributive property and substitute i^2 = -1: (a + bi)(c + di) = ac + adi + bci + bdi^2 = (ac - bd) + (ad + bc)i.\n * Division: Multiply the numerator and denominator by the complex conjugate of the denominator. The complex conjugate of a + bi is a - bi.

i = sqrt(-1), i^2 = -1
Fundamental Theorem of Algebra

Every polynomial function of degree n ≥ 1 with complex coefficients has at least one complex root. A direct consequence is that a polynomial function of degree n has exactly n roots (counting multiplicity) in the complex number system.

Conjugate Root Theorem

If a polynomial function P(x) with real coefficients has a complex root a + bi (where b ≠ 0), then its complex conjugate a - bi must also be a root.

Key facts to remember

  • 1A polynomial's degree is the highest exponent of the variable. The leading coefficient is the coefficient of the term with the highest degree.
  • 2The imaginary unit 'i' is defined as sqrt(-1), which means i^2 = -1. This is fundamental for complex number operations.
  • 3The Rational Root Theorem provides a list of possible rational roots p/q, where p divides the constant term and q divides the leading coefficient.
  • 4Synthetic division is an efficient method for dividing a polynomial by a linear factor (x - k) and for testing potential roots.
  • 5The Fundamental Theorem of Algebra states that a polynomial of degree n has exactly n roots in the complex number system (counting multiplicity).
  • 6The Conjugate Root Theorem states that if a polynomial with real coefficients has a complex root a + bi, then its conjugate a - bi must also be a root.
  • 7When multiplying complex numbers, always remember to replace i^2 with -1.
  • 8The powers of i cycle every four terms: i^1 = i, i^2 = -1, i^3 = -i, i^4 = 1.

Worked examples

Example 1

Given P(x) = 2x^3 - 3x^2 + 5x - 1 and Q(x) = x - 2, find the quotient P(x) / Q(x) using synthetic division.

I1. Set up the synthetic division. The divisor is (x - 2), so k = 2. Write the coefficients of P(x): 2, -3, 5, -1.
II2. Bring down the first coefficient: 2.
III3. Multiply 2 by k=2 to get 4. Write 4 under -3.
IV4. Add -3 + 4 = 1.
V5. Multiply 1 by k=2 to get 2. Write 2 under 5.
VI6. Add 5 + 2 = 7.
VII7. Multiply 7 by k=2 to get 14. Write 14 under -1.
VIII8. Add -1 + 14 = 13.
99. The last number, 13, is the remainder. The other numbers 2, 1, 7 are the coefficients of the quotient, which will be one degree less than P(x).

Answer

2x^2 + x + 7 + 13/(x - 2)

Synthetic division is only applicable when dividing by a linear factor of the form (x - k).

Example 2

Factor the polynomial P(x) = x^3 - 2x^2 + 4x - 8 completely over the complex numbers and find all its roots.

I1. Try factoring by grouping the first two terms and the last two terms: x^2(x - 2) + 4(x - 2).
II2. Factor out the common binomial (x - 2): (x - 2)(x^2 + 4).
III3. To find the roots, set P(x) = 0: (x - 2)(x^2 + 4) = 0.
IV4. Set each factor to zero and solve for x:\n * x - 2 = 0 => x = 2 (This is a real root).\n * x^2 + 4 = 0 => x^2 = -4.
V5. Take the square root of both sides for x^2 = -4: x = ±sqrt(-4) = ±sqrt(4 * -1) = ±2i (These are complex conjugate roots).
VI6. The factors are (x - 2), (x - 2i), and (x + 2i).

Answer

Factored form: (x - 2)(x - 2i)(x + 2i). Roots: x = 2, 2i, -2i.

This polynomial has degree 3, and we found 3 roots, consistent with the Fundamental Theorem of Algebra. The complex roots appear as a conjugate pair, consistent with the Conjugate Root Theorem.

Example 3

Write a polynomial function P(x) of least degree with real coefficients that has roots 3 and 1 - i.

I1. Since the polynomial has real coefficients and 1 - i is a root, its complex conjugate 1 + i must also be a root (by the Conjugate Root Theorem).
II2. The roots are 3, 1 - i, and 1 + i.
III3. The factors corresponding to these roots are (x - 3), (x - (1 - i)), and (x - (1 + i)).
IV4. Multiply the complex conjugate factors first: (x - (1 - i))(x - (1 + i)).\n Rewrite as: ((x - 1) + i)((x - 1) - i).\n This is in the form (A + B)(A - B) = A^2 - B^2, where A = (x - 1) and B = i.\n = (x - 1)^2 - i^2\n = (x^2 - 2x + 1) - (-1)\n = x^2 - 2x + 1 + 1\n = x^2 - 2x + 2
V5. Now multiply this result by the remaining factor (x - 3):\n P(x) = (x - 3)(x^2 - 2x + 2)\n P(x) = x(x^2 - 2x + 2) - 3(x^2 - 2x + 2)\n P(x) = x^3 - 2x^2 + 2x - 3x^2 + 6x - 6\n P(x) = x^3 - 5x^2 + 8x - 6

Answer

P(x) = x^3 - 5x^2 + 8x - 6

The degree of the polynomial is 3, which is the number of roots given or implied.

Common mistakes

  • ✗Sign errors in synthetic division: Forgetting to use 'k' from (x - k) correctly or making arithmetic errors during the addition/multiplication steps.
  • ✗Not checking for a Greatest Common Factor (GCF) first: Always factor out the GCF before attempting other factoring methods.
  • ✗Incorrectly handling i^2: Forgetting to substitute i^2 = -1 when multiplying complex numbers, or incorrectly simplifying higher powers of i.
  • ✗Not finding all roots: Stopping after finding only real roots, or forgetting to include complex conjugate pairs when applicable.
  • ✗Assuming all roots are real: Polynomials can have complex roots, especially when the degree is greater than 1.

Exam tips

  • ★Show all your work: Even if you can do a step in your head, writing it down helps prevent errors and allows for partial credit.
  • ★Check your factoring: Multiply your factors back together to ensure they equal the original polynomial.
  • ★Use synthetic division efficiently: It's a powerful tool for testing rational roots and reducing the degree of a polynomial, making further factoring easier.
  • ★When constructing polynomials from roots: Always multiply the complex conjugate pairs first, as this will result in a quadratic with real coefficients, simplifying subsequent multiplication.

Ready to practise?

Try a problem on this topic

Snap a photo or type a question — get step-by-step working instantly.