Class 10 — Mathematics (NCERT)

Circles: Tangents and Number of Tangents from a Point

Class 10

  • ✓By the end of this lesson students will be able to define a tangent to a circle and identify its point of contact.
  • ✓By the end of this lesson students will be able to state and apply the theorem that the tangent at any point of a circle is perpendicular to the radius through the point of contact.
  • ✓By the end of this lesson students will be able to determine the number of tangents that can be drawn to a circle from a point based on its position (inside, on, or outside the circle).
  • ✓By the end of this lesson students will be able to state and apply the theorem that the lengths of tangents drawn from an external point to a circle are equal.
  • ✓By the end of this lesson students will be able to solve problems involving tangents to a circle using geometric properties and the Pythagoras theorem.

Key concepts

Tangent to a Circle

A tangent to a circle is a line that intersects the circle at exactly one point. This unique point is called the point of contact. A tangent never enters the interior of the circle.

Theorem 10.1: Perpendicularity of Tangent and Radius

The tangent at any point of a circle is perpendicular to the radius through the point of contact. If a line AB is tangent to a circle with centre O at point P, then the radius OP is perpendicular to the tangent AB. This means ∠OPA = 90°.

OP ⊥ AB
Number of Tangents from a Point to a Circle

The number of tangents that can be drawn from a point to a circle depends on the position of the point relative to the circle:\n1. If the point lies inside the circle, no tangent can be drawn through it.\n2. If the point lies on the circle, exactly one tangent can be drawn through it.\n3. If the point lies outside the circle, exactly two tangents can be drawn from it to the circle.

Theorem 10.2: Lengths of Tangents from an External Point

The lengths of tangents drawn from an external point to a circle are equal. If P is an external point and PQ and PR are two tangents drawn from P to a circle with centre O, then PQ = PR.

PQ = PR

Key facts to remember

  • 1A tangent is a line that intersects a circle at exactly one point, called the point of contact.
  • 2Theorem 10.1: The tangent at any point of a circle is perpendicular to the radius through the point of contact.
  • 3No tangent can be drawn to a circle from a point lying inside it.
  • 4Exactly one tangent can be drawn to a circle from a point lying on it.
  • 5Exactly two tangents can be drawn to a circle from a point lying outside it.
  • 6Theorem 10.2: The lengths of tangents drawn from an external point to a circle are equal.
  • 7The Pythagoras theorem is frequently used in problems involving tangents and radii, as they often form right-angled triangles.

Worked examples

Example 1

A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Find the length of PQ.

IDraw a circle with centre O and radius OP = 5 cm.
IIDraw a tangent PQ at point P. Join OQ.
IIIAccording to Theorem 10.1, the radius OP is perpendicular to the tangent PQ at the point of contact P. Therefore, ∠OPQ = 90°.
IVIn the right-angled triangle ΔOPQ, we have OP = 5 cm (radius) and OQ = 12 cm (given).
VBy Pythagoras theorem, OQ² = OP² + PQ².
VISubstitute the given values: 12² = 5² + PQ².
VIISimplify: 144 = 25 + PQ².
VIIIRearrange to find PQ²: PQ² = 144 - 25 = 119.
9Take the square root: PQ = √119 cm.

Answer

The length of PQ is √119 cm.

Always draw a neat diagram to visualise the problem and identify the right-angled triangle.

Example 2

From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. Find the radius of the circle.

ILet the circle have centre O and radius 'r'. Let P be the point of contact of the tangent from Q.
IIWe are given that the length of the tangent PQ = 24 cm.
IIIThe distance of Q from the centre O is OQ = 25 cm.
IVAccording to Theorem 10.1, the radius OP is perpendicular to the tangent PQ at the point of contact P. Thus, ΔOPQ is a right-angled triangle with ∠OPQ = 90°.
VBy Pythagoras theorem, OQ² = OP² + PQ².
VISubstitute the given values: 25² = r² + 24².
VIISimplify: 625 = r² + 576.
VIIIRearrange to find r²: r² = 625 - 576 = 49.
9Take the square root: r = √49 = 7 cm.

Answer

The radius of the circle is 7 cm.

Remember that the radius is always perpendicular to the tangent at the point of contact, forming a right-angled triangle.

Example 3

Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.

ILet O be the common centre of the two concentric circles.
IILet the radius of the larger circle be R = 5 cm and the radius of the smaller circle be r = 3 cm.
IIILet AB be the chord of the larger circle that touches the smaller circle at point P.
IVSince AB is a tangent to the smaller circle at P, and OP is the radius of the smaller circle, by Theorem 10.1, OP ⊥ AB. So, ∠OPA = 90°.
VIn the right-angled triangle ΔOPA, OA is the radius of the larger circle (hypotenuse), so OA = R = 5 cm.
VIOP is the radius of the smaller circle, so OP = r = 3 cm.
VIIBy Pythagoras theorem, OA² = OP² + AP².
VIIISubstitute the values: 5² = 3² + AP².
9Simplify: 25 = 9 + AP².
10Rearrange to find AP²: AP² = 25 - 9 = 16.
11Take the square root: AP = √16 = 4 cm.
12Since the perpendicular from the centre to a chord bisects the chord, P is the midpoint of AB. Therefore, AB = 2 × AP.
13Calculate AB: AB = 2 × 4 cm = 8 cm.

Answer

The length of the chord of the larger circle is 8 cm.

This problem combines the tangent-radius perpendicularity with the property of a chord being bisected by a perpendicular from the centre.

Common mistakes

  • ✗Confusing a secant (a line intersecting a circle at two points) with a tangent.
  • ✗Incorrectly assuming that the angle between a tangent and a chord through the point of contact is 90 degrees, instead of the angle between the tangent and the radius.
  • ✗Applying Pythagoras theorem incorrectly by misidentifying the hypotenuse in a right-angled triangle.
  • ✗Forgetting that the perpendicular from the centre to a chord bisects the chord, which is often crucial in combined problems.
  • ✗Not drawing a clear and labelled diagram, leading to errors in understanding the relationships between lines and points.

Exam tips

  • ★Always draw a neat and labelled diagram for every problem. This helps in visualising the given information and identifying relevant geometric figures, especially right-angled triangles.
  • ★Clearly state the theorems you are using in your solution (e.g., 'By Theorem 10.1, OP ⊥ PQ'). This shows your understanding and earns marks.
  • ★Look for right-angled triangles formed by radii, tangents, and distances from the centre. The Pythagoras theorem is a very common tool in these problems.
  • ★Practice solving a variety of problems to become proficient in applying both Theorem 10.1 and Theorem 10.2, as well as other circle properties learned previously.

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