Section B — Chapters 23–39

Applied Measure II

Junior Cycle — 1st Year

  • By the end of this lesson students will be able to calculate the perimeter and area of triangles.
  • By the end of this lesson students will be able to calculate the perimeter (circumference) and area of discs (circles).
  • By the end of this lesson students will be able to calculate the perimeter and area of composite 2D shapes.
  • By the end of this lesson students will be able to calculate the volume of rectangular solids (cuboids) and cylinders.
  • By the end of this lesson students will be able to interpret and use scaled diagrams to find actual measurements.

Key concepts

Perimeter

The perimeter of a 2D shape is the total distance around its outer boundary. It is measured in units of length (e.g., cm, m).

Area

The area of a 2D shape is the amount of surface it covers. It is measured in square units (e.g., cm², m²).

Perimeter and Area of Triangles

A triangle is a polygon with three sides. To find its perimeter, add the lengths of all three sides. To find its area, multiply half of its base by its perpendicular height.

Perimeter = a + b + c\nArea = (1/2) × base × height
Perimeter (Circumference) and Area of Discs (Circles)

A disc (or circle) is a 2D shape where all points on its boundary are equidistant from a central point. The radius (r) is the distance from the centre to the boundary. The diameter (d) is the distance across the disc through the centre (d = 2r). The perimeter of a disc is called its circumference.

Circumference = 2πr or πd\nArea = πr²
Perimeter and Area of Combinations of Shapes (Composite Shapes)

Composite shapes are made up of two or more basic geometric shapes (e.g., rectangles, triangles, discs). To find their perimeter, add the lengths of all the outer edges. To find their area, break the shape down into simpler shapes, calculate the area of each, and then add or subtract them as appropriate.

Volume

The volume of a 3D object is the amount of space it occupies. It is measured in cubic units (e.g., cm³, m³).

Volume of Rectangular Solids (Cuboids)

A rectangular solid (or cuboid) is a 3D shape with six rectangular faces. Its volume is found by multiplying its length, width, and height.

Volume = length × width × height
Volume of Cylinders

A cylinder is a 3D shape with two parallel circular bases and a curved surface. Its volume is found by multiplying the area of its circular base by its height.

Volume = Area of base × height = πr²h
Scaled Diagrams

A scaled diagram is a drawing where all measurements are proportionally reduced or enlarged from the actual object. The scale is usually given as a ratio (e.g., 1:100), meaning 1 unit on the diagram represents 100 units in reality.

Actual measurement = Diagram measurement × Scale factor

Key facts to remember

  • 1Perimeter is the distance around a 2D shape, measured in units of length.
  • 2Area is the amount of surface a 2D shape covers, measured in square units.
  • 3Volume is the amount of space a 3D object occupies, measured in cubic units.
  • 4The value of π (pi) is approximately 3.14159 or 22/7, depending on the question's instruction.
  • 51 metre (m) = 100 centimetres (cm).
  • 61 m² = 10,000 cm².
  • 71 m³ = 1,000,000 cm³.
  • 81 litre = 1000 cm³.

Worked examples

Example 1

A triangle has sides of length 5 cm, 12 cm, and 13 cm. Its base is 12 cm and its perpendicular height is 5 cm. Calculate its perimeter and area.

ITo find the perimeter, add the lengths of all three sides:
IIPerimeter = 5 cm + 12 cm + 13 cm
IIIPerimeter = 30 cm
IVTo find the area, use the formula Area = (1/2) × base × height:
VArea = (1/2) × 12 cm × 5 cm
VIArea = (1/2) × 60 cm²
VIIArea = 30 cm²

Answer

Perimeter = 30 cm, Area = 30 cm²

Always ensure the height is perpendicular to the base used.

Example 2

A disc has a radius of 7 cm. Using π = 22/7, calculate its circumference and area.

ITo find the circumference, use the formula Circumference = 2πr:
IICircumference = 2 × (22/7) × 7 cm
IIICircumference = 2 × 22 cm
IVCircumference = 44 cm
VTo find the area, use the formula Area = πr²:
VIArea = (22/7) × (7 cm)²
VIIArea = (22/7) × 49 cm²
VIIIArea = 22 × 7 cm²
9Area = 154 cm²

Answer

Circumference = 44 cm, Area = 154 cm²

Pay attention to the value of π given in the question, if any.

Example 3

A shape is formed by a rectangle with length 10 cm and width 6 cm, with a semi-disc attached to one of its 6 cm sides. Calculate the total area of the shape. Use π = 3.14.

IBreak the shape into two parts: a rectangle and a semi-disc.
IICalculate the area of the rectangle:
IIIArea of rectangle = length × width = 10 cm × 6 cm = 60 cm²
IVThe diameter of the semi-disc is the width of the rectangle, which is 6 cm. So, the radius (r) of the semi-disc is 6 cm / 2 = 3 cm.
VCalculate the area of the full disc: Area = πr² = 3.14 × (3 cm)² = 3.14 × 9 cm² = 28.26 cm²
VICalculate the area of the semi-disc: Area of semi-disc = (1/2) × Area of full disc = (1/2) × 28.26 cm² = 14.13 cm²
VIIAdd the areas of the rectangle and the semi-disc to find the total area:
VIIITotal Area = Area of rectangle + Area of semi-disc = 60 cm² + 14.13 cm² = 74.13 cm²

Answer

Total Area = 74.13 cm²

For perimeter of composite shapes, only add the outer edges. The internal line between the rectangle and semi-disc is not part of the perimeter.

Example 4

A rectangular solid has a length of 8 cm, a width of 5 cm, and a height of 10 cm. Calculate its volume.

ITo find the volume of a rectangular solid, use the formula Volume = length × width × height:
IIVolume = 8 cm × 5 cm × 10 cm
IIIVolume = 40 cm² × 10 cm
IVVolume = 400 cm³

Answer

Volume = 400 cm³

Remember that volume is measured in cubic units.

Example 5

A cylindrical can has a radius of 3 cm and a height of 10 cm. Calculate its volume, giving your answer in terms of π.

ITo find the volume of a cylinder, use the formula Volume = πr²h:
IIVolume = π × (3 cm)² × 10 cm
IIIVolume = π × 9 cm² × 10 cm
IVVolume = 90π cm³

Answer

Volume = 90π cm³

If the question asks for the answer 'in terms of π', do not substitute a numerical value for π.

Example 6

A scaled diagram of a garden shows a path with a length of 4 cm. The scale of the diagram is 1:200. What is the actual length of the path in metres?

IThe scale 1:200 means that 1 cm on the diagram represents 200 cm in reality.
IIActual length in cm = Diagram length × Scale factor
IIIActual length = 4 cm × 200
IVActual length = 800 cm
VConvert the actual length from centimetres to metres (1 m = 100 cm):
VIActual length in metres = 800 cm / 100 cm/m
VIIActual length = 8 m

Answer

The actual length of the path is 8 m.

Always check if the question requires the answer in specific units (e.g., metres instead of centimetres).

Common mistakes

  • Confusing the formulas for perimeter and area, or circumference and area.
  • Using the diameter instead of the radius (or vice versa) in disc/cylinder formulas.
  • Forgetting to include the correct units (cm, cm², cm³) in the final answer.
  • Incorrectly identifying the base and perpendicular height for the area of a triangle.
  • Not dividing by 2 when calculating the area or circumference of a semi-disc.
  • Misinterpreting the scale in scaled diagrams (e.g., dividing instead of multiplying, or vice versa).

Exam tips

  • Always draw a clear diagram for the problem if one isn't provided, or add labels to an existing one.
  • Write down the correct formula before substituting any values into it.
  • Show all your steps clearly and logically, as marks are awarded for working.
  • Double-check your calculations, especially when using π or dealing with multiple steps.
  • Read the question carefully to ensure you answer exactly what is asked, including units and level of precision (e.g., 'in terms of π' or 'to one decimal place').

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