Geometry & measures

Vectors (Higher)

Year 10 · Year 11

  • Understand and use standard vector notation, including column vectors and bold letters.
  • Perform vector addition, subtraction, and scalar multiplication both graphically and using components.
  • Calculate the magnitude of a vector using Pythagoras' theorem.
  • Use vectors to solve geometric problems and prove geometric facts, including showing points are collinear or lines are parallel.

Key concepts

Vector

A quantity that has both magnitude (size) and direction. Examples include displacement, velocity, and force. This contrasts with a scalar, which only has magnitude (e.g., speed, mass, temperature).

Vector Notation

Vectors are typically represented in textbooks by bold lowercase letters (e.g., a, b). When writing by hand, an arrow above the letter is used (e.g., →a, →AB). A column vector (x, y) represents a displacement of x units horizontally and y units vertically. A position vector is a vector from the origin (O) to a point (e.g., →OA or a). A displacement vector is a vector representing the displacement from one point to another (e.g., →AB).

Magnitude of a Vector

The length or size of a vector. For a vector a = (x, y), its magnitude, denoted |a|, is calculated using Pythagoras' theorem.

|a| = √(x² + y²)
Vector Addition and Subtraction

To add or subtract two vectors, add or subtract their corresponding components. Graphically, for addition, place the tail of the second vector at the head of the first; the resultant vector goes from the tail of the first to the head of the second (triangle rule). For subtraction, a - b is equivalent to a + (-b), where -b has the same magnitude as b but the opposite direction. The displacement vector →AB is found by →OB - →OA, where →OA and →OB are position vectors.

If a = (x₁, y₁) and b = (x₂, y₂), then a + b = (x₁ + x₂, y₁ + y₂) and a - b = (x₁ - x₂, y₁ - y₂)
Scalar Multiplication

Multiplying a vector by a scalar (a number) changes its magnitude but not its direction (unless the scalar is negative, which reverses the direction). Each component of the vector is multiplied by the scalar.

If a = (x, y) and k is a scalar, then ka = (kx, ky)
Parallel Vectors

Two non-zero vectors a and b are parallel if one is a scalar multiple of the other. This means they have the same or opposite direction.

b = ka for some scalar k
Collinear Points

Three or more points A, B, C are collinear if they lie on the same straight line. This can be proven by showing that the vector →AB is a scalar multiple of →BC (or →AC), and that they share a common point (e.g., B).

→AB = k→BC (and B is a common point)

Key facts to remember

  • 1A vector has both magnitude (size) and direction.
  • 2A column vector (x, y) represents a displacement of x units horizontally and y units vertically.
  • 3The magnitude of a vector a = (x, y) is |a| = √(x² + y²).
  • 4The vector from point A to point B is →AB = →OB - →OA, where →OA and →OB are position vectors.
  • 5If vector b is a scalar multiple of vector a (i.e., b = ka), then a and b are parallel.
  • 6Points A, B, C are collinear if →AB is a scalar multiple of →BC (or →AC), and they share a common point.
  • 7The negative of a vector, -a, has the same magnitude but opposite direction to a.

Worked examples

Example 1

Given vectors a = (4, -1) and b = (-2, 3), find: a) a + b b) 3a c) 2a - b

Ia) a + b = (4, -1) + (-2, 3) = (4 + (-2), -1 + 3) = (2, 2)
IIb) 3a = 3 × (4, -1) = (3 × 4, 3 × -1) = (12, -3)
IIIc) 2a - b = 2 × (4, -1) - (-2, 3) = (8, -2) - (-2, 3) = (8 - (-2), -2 - 3) = (10, -5)

Answer

a) (2, 2) b) (12, -3) c) (10, -5)

Remember to add or subtract corresponding components for vector arithmetic.

Example 2

Points P, Q and R have position vectors p = (1, 5), q = (7, 2) and r = (0, 10) respectively. a) Find the vector →PQ. b) Calculate the magnitude of →PR. c) Show that P, Q and R are not collinear.

Ia) →PQ = q - p = (7, 2) - (1, 5) = (7 - 1, 2 - 5) = (6, -3)
IIb) First, find →PR = r - p = (0, 10) - (1, 5) = (0 - 1, 10 - 5) = (-1, 5). Now, calculate the magnitude: |→PR| = √((-1)² + 5²) = √(1 + 25) = √26.
IIIc) For P, Q, R to be collinear, →PQ must be a scalar multiple of →PR. We have →PQ = (6, -3) and →PR = (-1, 5). If →PQ = k→PR, then (6, -3) = k(-1, 5) = (-k, 5k). Comparing the x-components: 6 = -k ⇒ k = -6. Comparing the y-components: -3 = 5k ⇒ k = -3/5. Since the value of k is not consistent, →PQ is not a scalar multiple of →PR. Therefore, P, Q and R are not collinear.

Answer

a) (6, -3) b) √26 c) P, Q and R are not collinear because →PQ is not a scalar multiple of →PR.

When proving collinearity, you must show that the vectors are parallel AND share a common point. If they are not parallel, they cannot be collinear.

Example 3

OABC is a parallelogram. M is the midpoint of AC. Given that →OA = a and →OC = c. a) Express →OB in terms of a and c. b) Express →OM in terms of a and c.

Ia) In a parallelogram, opposite sides are parallel and equal in length, so →AB = →OC = c. To find →OB, we can follow the path from O to A then A to B: →OB = →OA + →AB →OB = a + c
IIb) To find →OM, we can follow the path from O to A then A to M: →OM = →OA + →AM First, find →AC: →AC = →AO + →OC = -a + c = c - a. Since M is the midpoint of AC, →AM = 1/2 × →AC. →AM = 1/2(c - a). Now substitute this back into the expression for →OM: →OM = a + 1/2(c - a) →OM = a + 1/2c - 1/2a →OM = 1/2a + 1/2c →OM = 1/2(a + c)

Answer

a) →OB = a + c b) →OM = 1/2(a + c)

Drawing a diagram for geometric vector problems can greatly help in visualising the paths and relationships between vectors.

Common mistakes

  • Confusing the coordinates of a point with its position vector.
  • Incorrectly performing vector subtraction, e.g., writing →AB = →OA - →OB instead of →OB - →OA.
  • Forgetting to state the common point when proving collinearity (e.g., just showing parallelism is not enough).
  • Treating vectors as scalars, such as attempting to divide vectors or performing non-scalar multiplication.
  • Errors in algebraic manipulation when simplifying vector expressions, especially with negative signs.

Exam tips

  • Always draw a clear diagram for geometric vector problems to help visualise the paths and relationships between vectors.
  • Show all steps in your working, especially for proofs, clearly stating any reasons or conditions (e.g., 'since they share a common point...').
  • Use correct vector notation throughout your answer (e.g., bold letters in print or arrows above letters when handwritten).
  • Check your calculations carefully, particularly when dealing with negative numbers in column vectors.

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