Functions & Algebra

Quadratic and Polynomial Functions: Factoring, Quadratic Formula, and Graphing

Grade 10 · Grade 11 · Grade 12

  • ✓By the end of this lesson students will be able to factor quadratic expressions using various methods.
  • ✓By the end of this lesson students will be able to solve quadratic equations using the quadratic formula.
  • ✓By the end of this lesson students will be able to graph quadratic functions, identifying key features like the vertex, axis of symmetry, and intercepts.
  • ✓By the end of this lesson students will be able to understand the basic properties of polynomial functions, including degree and end behaviour.
  • ✓By the end of this lesson students will be able to determine the nature of the roots of a quadratic equation using the discriminant.

Key concepts

Quadratic Functions

A quadratic function is a polynomial function of degree 2. Its graph is a parabola. The standard form is y = ax^2 + bx + c, where a, b, and c are real numbers and a ≠ 0. The vertex form is y = a(x - h)^2 + k, where (h, k) is the vertex. The factored form is y = a(x - r_1)(x - r_2), where r_1 and r_2 are the x-intercepts (zeros or roots).

y = ax^2 + bx + c
Factoring Quadratic Expressions

Factoring a quadratic expression means writing it as a product of two linear expressions. Common methods include common factoring (e.g., ax^2 + bx = x(ax + b)), factoring simple trinomials (x^2 + bx + c), factoring complex trinomials (ax^2 + bx + c, often using decomposition), and factoring the difference of squares (a^2 - b^2 = (a - b)(a + b)). Factoring helps find the zeros of the function.

Quadratic Formula

The quadratic formula is used to find the roots (or zeros) of any quadratic equation in the form ax^2 + bx + c = 0. It can be used when factoring is difficult or impossible. The solutions are given by the formula.

x = (-b ± sqrt(b^2 - 4ac)) / (2a)
The Discriminant

The discriminant is the part of the quadratic formula under the square root sign, Δ = b^2 - 4ac. It determines the nature of the roots of a quadratic equation: If Δ > 0, there are two distinct real roots. If Δ = 0, there is one real root (or two equal real roots). If Δ < 0, there are no real roots (two complex conjugate roots).

Δ = b^2 - 4ac
Graphing Quadratic Functions

To graph a quadratic function, identify key features: the direction of opening (up if a > 0, down if a < 0), the vertex (the turning point of the parabola, (h, k) from vertex form or x = -b/(2a) for the x-coordinate), the axis of symmetry (the vertical line x = h or x = -b/(2a)), the y-intercept (set x = 0, which is 'c' in standard form), and the x-intercepts (set y = 0, solve by factoring or quadratic formula).

Polynomial Functions (Introduction)

A polynomial function is a function of the form P(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0, where a_n ≠ 0, n is a non-negative integer, and a_i are real coefficients. The highest exponent, n, is the degree of the polynomial. The coefficient a_n is the leading coefficient. The degree and leading coefficient determine the end behaviour of the graph (how the graph behaves as x approaches positive or negative infinity).

P(x) = a_n x^n + a_{n-1} x^{n-1} + ... + a_1 x + a_0

Key facts to remember

  • 1The standard form of a quadratic function is y = ax^2 + bx + c, where a ≠ 0.
  • 2The vertex of a parabola is its turning point, and the axis of symmetry passes through it.
  • 3The x-intercepts of a quadratic function are also called its zeros or roots.
  • 4The quadratic formula x = (-b ± sqrt(b^2 - 4ac)) / (2a) can solve any quadratic equation.
  • 5The discriminant, Δ = b^2 - 4ac, tells you the number and type of real roots.
  • 6Factoring is a method to express a quadratic as a product of linear factors, useful for finding integer roots.
  • 7The degree of a polynomial function is its highest exponent, which influences its end behaviour.

Worked examples

Example 1

Factor the quadratic expression 3x^2 - 10x - 8 and find its zeros.

IIdentify a, b, c: a = 3, b = -10, c = -8.
IIFind two numbers that multiply to (a * c) = (3 * -8) = -24 and add to b = -10. These numbers are -12 and 2.
IIIDecompose the middle term: 3x^2 - 12x + 2x - 8.
IVGroup terms and common factor: (3x^2 - 12x) + (2x - 8) = 3x(x - 4) + 2(x - 4).
VFactor out the common binomial: (x - 4)(3x + 2).
VITo find the zeros, set each factor to zero: x - 4 = 0 => x = 4.
VIIAnd 3x + 2 = 0 => 3x = -2 => x = -2/3.

Answer

The factored form is (x - 4)(3x + 2). The zeros are x = 4 and x = -2/3.

This is an example of factoring a complex trinomial using the decomposition method.

Example 2

Solve the quadratic equation 2x^2 + 4x - 5 = 0 using the quadratic formula. Round answers to two decimal places.

IIdentify a, b, c: a = 2, b = 4, c = -5.
IISubstitute the values into the quadratic formula: x = (-b ± sqrt(b^2 - 4ac)) / (2a).
IIIx = (-(4) ± sqrt((4)^2 - 4(2)(-5))) / (2(2)).
IVx = (-4 ± sqrt(16 - (-40))) / 4.
Vx = (-4 ± sqrt(16 + 40)) / 4.
VIx = (-4 ± sqrt(56)) / 4.
VIICalculate sqrt(56) ≈ 7.48.
VIIIx_1 = (-4 + 7.48) / 4 = 3.48 / 4 = 0.87.
9x_2 = (-4 - 7.48) / 4 = -11.48 / 4 = -2.87.

Answer

The solutions are x ≈ 0.87 and x ≈ -2.87.

Always check the discriminant first if you're unsure if factoring is possible or if you need to know the nature of the roots.

Example 3

Graph the quadratic function y = -x^2 + 2x + 3. Identify the vertex, axis of symmetry, y-intercept, and x-intercepts.

IIdentify a, b, c: a = -1, b = 2, c = 3. Since a < 0, the parabola opens downwards.
IIFind the x-coordinate of the vertex: x = -b/(2a) = -(2)/(2(-1)) = -2/-2 = 1.
IIIFind the y-coordinate of the vertex by substituting x = 1 into the equation: y = -(1)^2 + 2(1) + 3 = -1 + 2 + 3 = 4. So, the vertex is (1, 4).
IVThe axis of symmetry is the vertical line x = 1.
VFind the y-intercept by setting x = 0: y = -(0)^2 + 2(0) + 3 = 3. The y-intercept is (0, 3).
VIFind the x-intercepts (zeros) by setting y = 0: -x^2 + 2x + 3 = 0. Multiply by -1: x^2 - 2x - 3 = 0.
VIIFactor the quadratic: (x - 3)(x + 1) = 0. So, x - 3 = 0 => x = 3, and x + 1 = 0 => x = -1. The x-intercepts are (3, 0) and (-1, 0).
VIIIPlot the vertex (1, 4), y-intercept (0, 3), and x-intercepts (3, 0), (-1, 0). Use the symmetry to find another point, e.g., if (0, 3) is on the graph, then (2, 3) is also on the graph (since x=1 is the axis of symmetry).
9Draw a smooth parabola through these points.

Answer

The graph is a parabola opening downwards with: Vertex: (1, 4), Axis of Symmetry: x = 1, Y-intercept: (0, 3), X-intercepts: (-1, 0) and (3, 0).

Sketching the graph helps visualize the function's behaviour and verify your calculated points.

Common mistakes

  • ✗Incorrectly applying the signs in the quadratic formula, especially with negative 'b' or 'c' values.
  • ✗Forgetting to divide the entire numerator by '2a' in the quadratic formula.
  • ✗Making arithmetic errors when calculating the discriminant or simplifying square roots.
  • ✗Confusing the x-coordinate of the vertex (-b/2a) with the axis of symmetry (x = -b/2a).
  • ✗Assuming all quadratic expressions can be factored easily; some require the quadratic formula.

Exam tips

  • ★Always check your factored expressions by expanding them to ensure they match the original quadratic.
  • ★When using the quadratic formula, write down the values of a, b, and c first to avoid substitution errors.
  • ★For graphing, always find the vertex, intercepts, and direction of opening. Use symmetry to find additional points.
  • ★If a question asks for 'exact' roots, leave your answer in simplified radical form; do not round.

Ready to practise?

Try a problem on this topic

Snap a photo or type a question — get step-by-step working instantly.