Measurement, Space & Statistics

Circles, Volume and Congruence

Year 8

  • ✓By the end of this lesson students will be able to calculate the circumference and area of circles.
  • ✓By the end of this lesson students will be able to calculate the volume of prisms, including rectangular prisms, triangular prisms, and cylinders.
  • ✓By the end of this lesson students will be able to identify and apply the conditions for congruent triangles (SSS, SAS, ASA, RHS).
  • ✓By the end of this lesson students will be able to solve practical problems involving circles, volume, and congruence.

Key concepts

Circles: Circumference

The circumference of a circle is the distance around its edge. It is directly proportional to the diameter. The constant of proportionality is pi (π), an irrational number approximately equal to 3.14159. The radius (r) is the distance from the centre to the edge, and the diameter (d) is the distance across the circle through the centre (d = 2r).

C = πd or C = 2πr
Circles: Area

The area of a circle is the amount of two-dimensional space it covers within its boundary. It is calculated using the radius and pi.

A = πr²
Volume of Prisms

Volume is the amount of three-dimensional space an object occupies. A prism is a three-dimensional solid with two identical, parallel ends (bases) and flat sides. Its volume is found by multiplying the area of its base by its perpendicular height.

V = A_base × h
Volume of Specific Prisms

Using the general prism formula, specific formulas can be derived:\n- **Rectangular Prism**: V = length × width × height (V = lwh)\n- **Triangular Prism**: V = (1/2 × base_triangle × height_triangle) × height_prism\n- **Cylinder**: A cylinder is a type of prism with circular bases. Its base area is A_base = πr², so its volume is V = πr²h.

Congruence

Two geometric figures are congruent if they have exactly the same shape and the same size. This means that all corresponding sides are equal in length and all corresponding angles are equal in measure. The symbol for congruence is '≅'.

Conditions for Congruent Triangles

To prove two triangles are congruent, we don't need to show all six pairs of corresponding parts are equal. We only need to show one of the following four conditions:\n- **SSS (Side-Side-Side)**: If all three corresponding sides are equal in length.\n- **SAS (Side-Angle-Side)**: If two corresponding sides and the included angle (the angle between those two sides) are equal.\n- **ASA (Angle-Side-Angle)**: If two corresponding angles and the included side (the side between those two angles) are equal.\n- **RHS (Right-angle-Hypotenuse-Side)**: If both triangles are right-angled, and their hypotenuses and one pair of corresponding sides are equal.

Key facts to remember

  • 1π (pi) is the ratio of a circle's circumference to its diameter, approximately 3.14159.
  • 2Circumference of a circle: C = 2πr or C = πd.
  • 3Area of a circle: A = πr².
  • 4Volume of any prism: V = A_base × h.
  • 5Volume of a cylinder: V = πr²h.
  • 6Congruent figures have the same shape and size.
  • 7The four conditions for proving triangle congruence are SSS, SAS, ASA, and RHS.
  • 8Units for circumference are linear (e.g., cm), for area are square (e.g., cm²), and for volume are cubic (e.g., cm³).

Worked examples

Example 1

A circular garden bed has a radius of 3.5 metres. Calculate its circumference and area, correct to two decimal places. (Use π ≈ 3.14159)

IIdentify given values: r = 3.5 m.
IICircumference formula: C = 2πr.
IIISubstitute values: C = 2 × 3.14159 × 3.5.
IVCalculate: C ≈ 21.99113.
VRound to two decimal places: C ≈ 21.99 m.
VIArea formula: A = πr².
VIISubstitute values: A = 3.14159 × (3.5)².
VIIICalculate: A = 3.14159 × 12.25.
9Calculate: A ≈ 38.4845775.
10Round to two decimal places: A ≈ 38.48 m².

Answer

The circumference is approximately 21.99 m and the area is approximately 38.48 m².

Always remember to include the correct units for your answer.

Example 2

Calculate the volume of a cylindrical water tank with a radius of 1.2 metres and a height of 2.5 metres. Give your answer correct to one decimal place. (Use π ≈ 3.14159)

IIdentify given values: r = 1.2 m, h = 2.5 m.
IIVolume of a cylinder formula: V = πr²h.
IIISubstitute values: V = 3.14159 × (1.2)² × 2.5.
IVCalculate (1.2)²: V = 3.14159 × 1.44 × 2.5.
VCalculate: V = 3.14159 × 3.6.
VICalculate: V ≈ 11.309724.
VIIRound to one decimal place: V ≈ 11.3 m³.

Answer

The volume of the cylindrical water tank is approximately 11.3 m³.

Volume is measured in cubic units (e.g., m³, cm³).

Example 3

In the diagram below, AB is parallel to DC, and AD is parallel to BC. Prove that triangle ABD is congruent to triangle CDB.

IConsider the two triangles ΔABD and ΔCDB.
II1. ∠ABD = ∠CDB (Alternate angles are equal, as AB || DC).
III2. ∠ADB = ∠CBD (Alternate angles are equal, as AD || BC).
IV3. BD = DB (Common side to both triangles).
VTherefore, ΔABD ≅ ΔCDB (ASA: Angle-Side-Angle congruence condition).

Answer

Triangle ABD is congruent to triangle CDB (ASA).

Clearly state the reason for each equality and the congruence condition used. A diagram showing a parallelogram ABCD with diagonal BD would be helpful for this problem.

Common mistakes

  • ✗Confusing the formulas for circumference (2πr) and area (πr²).
  • ✗Using diameter instead of radius (or vice-versa) in formulas without adjusting.
  • ✗Forgetting to square the radius when calculating the area of a circle or volume of a cylinder.
  • ✗Not identifying the correct corresponding sides or angles when proving congruence.
  • ✗Incorrectly applying congruence conditions (e.g., using SSA, which is not a valid condition).

Exam tips

  • ★Always write down the correct formula before substituting values.
  • ★Show all working steps clearly, especially for congruence proofs, stating reasons for each step.
  • ★Pay close attention to units and ensure your final answer has the correct units (m, m², m³).
  • ★Read the question carefully to determine if you need to use radius or diameter, and what level of rounding is required.
  • ★For congruence, draw and label diagrams carefully to help identify corresponding parts.

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