Specialist Mathematics

Complex Numbers and Vectors

Year 11 · Year 12

  • ✓Perform arithmetic operations with complex numbers in Cartesian form.
  • ✓Convert complex numbers between Cartesian, polar, and exponential forms.
  • ✓Represent vectors in two and three dimensions using various notations.
  • ✓Perform arithmetic operations with vectors, including scalar multiplication, addition, and subtraction.
  • ✓Calculate the dot product and cross product of vectors and interpret their geometric significance.

Key concepts

Introduction to Complex Numbers

A complex number is a number that can be expressed in the form z = x + iy, where x and y are real numbers, and 'i' is the imaginary unit, satisfying i² = -1. 'x' is called the real part (Re(z)) and 'y' is called the imaginary part (Im(z)).

i² = -1
Complex Conjugate

The complex conjugate of z = x + iy is denoted as z̄ (read as 'z bar') and is given by z̄ = x - iy. The product of a complex number and its conjugate is always a real number: z * z̄ = x² + y².

z̄ = x - iy
Arithmetic Operations with Complex Numbers (Cartesian Form)

Given z₁ = x₁ + iy₁ and z₂ = x₂ + iy₂:\n- Addition: z₁ + z₂ = (x₁ + x₂) + i(y₁ + y₂)\n- Subtraction: z₁ - z₂ = (x₁ - x₂) + i(y₁ - y₂)\n- Multiplication: z₁z₂ = (x₁x₂ - y₁y₂) + i(x₁y₂ + x₂y₁)\n- Division: z₁/z₂ = (z₁ * z̄₂)/(z₂ * z̄₂). Multiply the numerator and denominator by the conjugate of the denominator.

Polar Form of Complex Numbers

A complex number z = x + iy can be represented in polar form as z = r(cos θ + i sin θ), where 'r' is the modulus (distance from the origin to z on the Argand diagram) and 'θ' is the argument (angle measured anticlockwise from the positive real axis to the line segment connecting the origin to z). r = |z| = √(x² + y²) and θ = arg(z). The principal argument is typically in the range -π < θ ≤ π.

z = r(cos θ + i sin θ)
Exponential Form of Complex Numbers (Euler's Formula)

Using Euler's formula, e^(iθ) = cos θ + i sin θ, the polar form can be written as z = re^(iθ). This form is particularly useful for multiplication, division, powers, and roots of complex numbers.

z = re^(iθ)
De Moivre's Theorem

For any integer n, De Moivre's Theorem states that (r(cos θ + i sin θ))^n = r^n(cos(nθ) + i sin(nθ)). This theorem is fundamental for finding powers and roots of complex numbers.

(r(cos θ + i sin θ))^n = r^n(cos(nθ) + i sin(nθ))
Introduction to Vectors

A vector is a quantity that has both magnitude (size) and direction. Examples include displacement, velocity, and force. A scalar quantity, such as mass or temperature, has only magnitude.

Vector Representation (2D and 3D)

Vectors can be represented in component form, column vector form, or using unit vector notation:\n- Component form: v = (x, y) for 2D, v = (x, y, z) for 3D.\n- Column vector: v = [x, y] for 2D, v = [x, y, z] for 3D.\n- Unit vector notation: v = xi + yj for 2D, v = xi + yj + zk for 3D, where i, j, k are standard unit vectors along the x, y, z axes respectively.

Magnitude of a Vector

The magnitude (or length) of a vector v = (x, y, z) is denoted by |v| and is calculated using the Pythagorean theorem.

|v| = √(x² + y² + z²)
Unit Vectors

A unit vector is a vector with a magnitude of 1. The unit vector in the same direction as a non-zero vector v is denoted by v̂ and is found by dividing the vector by its magnitude.

v̂ = v/|v|
Position Vectors

A position vector represents the position of a point relative to the origin. If P is a point (x, y, z), its position vector is OP = (x, y, z). The vector from point A to point B is given by AB = OB - OA, where OA and OB are the position vectors of A and B respectively.

AB = OB - OA
Vector Arithmetic

Given a = (a₁, a₂, a₃) and b = (b₁, b₂, b₃):\n- Addition: a + b = (a₁ + b₁, a₂ + b₂, a₃ + b₃)\n- Subtraction: a - b = (a₁ - b₁, a₂ - b₂, a₃ - b₃)\n- Scalar Multiplication: For a scalar k, k * a = (ka₁, ka₂, ka₃).

Dot Product (Scalar Product)

The dot product of two vectors a and b is a scalar quantity defined as a ⋅ b = |a||b|cos θ, where θ is the angle between the vectors. In component form, a ⋅ b = a₁b₁ + a₂b₂ + a₃b₃. If a ⋅ b = 0 for non-zero vectors, then a and b are perpendicular.

a ⋅ b = a₁b₁ + a₂b₂ + a₃b₃
Cross Product (Vector Product)

The cross product of two 3D vectors a and b is a vector quantity defined as a × b = |a||b|sin θ n̂, where n̂ is a unit vector perpendicular to both a and b, determined by the right-hand rule. The magnitude |a × b| represents the area of the parallelogram formed by a and b. In component form:\na × b = (a₂b₃ - a₃b₂, a₃b₁ - a₁b₃, a₁b₂ - a₂b₁). If a × b = 0 for non-zero vectors, then a and b are parallel.

a × b = (a₂b₃ - a₃b₂, a₃b₁ - a₁b₃, a₁b₂ - a₂b₁)

Key facts to remember

  • 1The imaginary unit i satisfies i² = -1.
  • 2The complex conjugate of z = x + iy is z̄ = x - iy.
  • 3The modulus of z = x + iy is |z| = √(x² + y²).
  • 4Euler's formula: e^(iθ) = cos θ + i sin θ.
  • 5A vector has both magnitude and direction, while a scalar has only magnitude.
  • 6If a ⋅ b = 0 (for non-zero vectors), then vectors a and b are perpendicular.
  • 7If a × b = 0 (for non-zero vectors), then vectors a and b are parallel.
  • 8The magnitude of the cross product, |a × b|, represents the area of the parallelogram formed by vectors a and b.

Worked examples

Example 1

Given z₁ = 2 + 3i and z₂ = 1 - 2i, calculate:\n(a) z₁z₂\n(b) z₁/z₂

I(a) z₁z₂ = (2 + 3i)(1 - 2i)
II = 2(1) + 2(-2i) + 3i(1) + 3i(-2i)
III = 2 - 4i + 3i - 6i²
IV = 2 - i - 6(-1)
V = 2 - i + 6
VI = 8 - i
VII(b) z₁/z₂ = (2 + 3i)/(1 - 2i)
VIII Multiply numerator and denominator by the conjugate of z₂ (which is 1 + 2i):
9 = [(2 + 3i)(1 + 2i)] / [(1 - 2i)(1 + 2i)]
10 Numerator: (2 + 3i)(1 + 2i) = 2(1) + 2(2i) + 3i(1) + 3i(2i)
11 = 2 + 4i + 3i + 6i²
12 = 2 + 7i - 6
13 = -4 + 7i
14 Denominator: (1 - 2i)(1 + 2i) = 1² - (2i)²
15 = 1 - 4i²
16 = 1 - 4(-1)
17 = 1 + 4
18 = 5
19 So, z₁/z₂ = (-4 + 7i)/5

Answer

(a) 8 - i\n(b) -4/5 + 7/5i

Remember that i² = -1. When dividing, always multiply by the conjugate of the denominator to make it a real number.

Example 2

Given vectors a = (1, -2, 3) and b = (4, 0, -1), calculate:\n(a) |a|\n(b) 2a - b\n(c) a ⋅ b\n(d) a × b

I(a) |a| = √(1² + (-2)² + 3²)
II = √(1 + 4 + 9)
III = √14
IV(b) 2a - b = 2(1, -2, 3) - (4, 0, -1)
V = (2*1, 2*(-2), 2*3) - (4, 0, -1)
VI = (2, -4, 6) - (4, 0, -1)
VII = (2 - 4, -4 - 0, 6 - (-1))
VIII = (-2, -4, 7)
9(c) a ⋅ b = (1)(4) + (-2)(0) + (3)(-1)
10 = 4 + 0 - 3
11 = 1
12(d) a × b = (a₂b₃ - a₃b₂, a₃b₁ - a₁b₃, a₁b₂ - a₂b₁)
13 = ((-2)(-1) - (3)(0), (3)(4) - (1)(-1), (1)(0) - (-2)(4))
14 = (2 - 0, 12 - (-1), 0 - (-8))
15 = (2, 13, 8)

Answer

(a) √14\n(b) (-2, -4, 7)\n(c) 1\n(d) (2, 13, 8)

The dot product results in a scalar, while the cross product results in a vector.

Example 3

Convert the complex number z = -1 + √3i to polar and exponential form.

IFirst, find the modulus r:
IIr = |z| = √((-1)² + (√3)²) = √(1 + 3) = √4 = 2
IIINext, find the argument θ. Sketch the complex number on an Argand diagram. z = -1 + √3i is in the second quadrant.
IVThe reference angle α = arctan(|√3 / -1|) = arctan(√3) = π/3 radians.
VSince z is in the second quadrant, θ = π - α = π - π/3 = 2π/3 radians.
VIPolar form: z = r(cos θ + i sin θ) = 2(cos(2π/3) + i sin(2π/3))
VIIExponential form: z = re^(iθ) = 2e^(i2π/3)

Answer

Polar form: 2(cos(2π/3) + i sin(2π/3))\nExponential form: 2e^(i2π/3)

Always sketch the complex number to correctly determine the argument's quadrant.

Common mistakes

  • ✗Incorrectly simplifying powers of 'i', especially i² = -1.
  • ✗Forgetting to multiply by the complex conjugate of the denominator when performing complex division.
  • ✗Calculating the argument (θ) of a complex number incorrectly, especially when it's not in the first quadrant.
  • ✗Confusing the dot product (scalar result) with the cross product (vector result).
  • ✗Errors in the order of components or signs when calculating the cross product of vectors.

Exam tips

  • ★Always simplify complex number expressions to the standard Cartesian form (x + iy) unless otherwise specified.
  • ★When converting complex numbers to polar or exponential form, draw an Argand diagram to correctly determine the quadrant and principal argument.
  • ★Show all steps clearly for vector calculations, especially for dot and cross products, to avoid arithmetic errors and gain partial marks.
  • ★Be precise with notation: 'i' for the imaginary unit versus 'i' for the x-axis unit vector. Context usually clarifies, but clarity is key.

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